Decrypt The Mystery Of 119707-74-3

Compounds in my other articles are similar to this one((S)-3,3′-Dibromo-1,1′-bi-2-naphthol)Formula: C20H12Br2O2, you can compare them to see their pros and cons in some ways,such as convenient, effective and so on.

The three-dimensional configuration of the ester heterocycle is basically the same as that of the carbocycle. Compound: (S)-3,3′-Dibromo-1,1′-bi-2-naphthol(SMILESS: OC1=C(Br)C=C2C=CC=CC2=C1C3=C4C=CC=CC4=CC(Br)=C3O,cas:119707-74-3) is researched.Quality Control of 4,4-Dipyridyl Disulfide. The article 《Novel binuclear chiral zirconium catalysts used in enantioselective Strecker reactions》 in relation to this compound, is published in Chirality. Let’s take a look at the latest research on this compound (cas:119707-74-3).

A novel binuclear chiral zirconium catalyst was successfully used in enantioselective Strecker reactions. The catalyst was readily prepared from zirconium t-butoxide, (R)-6,6′-dibromo-1,1′-bi-2-naphthol [(R)-6-Br-BINOL], and (R)-3,3′-dibromo-1,1′-bi-2-naphthol [(R)-3-Br-BINOL] to form a binuclear zirconium complex. It was revealed that a combination of (R)-6-Br-BINOL and (R)-3-Br-BINOL was essential in these asym. reactions and that much lower selectivities were obtained by using other combinations. Two-component [an imine and hydrogen cyanide (HCN)] and three-component (an aldehyde, an amine, and HCN) Strecker reactions proceeded smoothly in the presence of a catalytic amount of the chiral zirconium catalyst to afford the corresponding α-amino nitrile derivatives in high yields with high enantioselectivities. E.g., zirconium tert-butoxide was added to a solution of (R)-6-Br-BINOL, (R)-3-Br-BINOL, and N-methylimidazole in CH2Cl2; an HCN solution in CH2Cl2 was added at 0° and the mixture stirred for 3 h; the catalyst mixture was added to a solution of benzenepropanal and 2-amino-3-methylphenol in CH2Cl2 at -45° and stirred for 12 h to give, after workup, amino nitrile I in 85% yield and in 94% ee.

Compounds in my other articles are similar to this one((S)-3,3′-Dibromo-1,1′-bi-2-naphthol)Formula: C20H12Br2O2, you can compare them to see their pros and cons in some ways,such as convenient, effective and so on.

Reference:
Bromide – Wikipedia,
bromide – Wiktionary